Exponential equation :
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$\displaystyle x^y=y^x$ it is hard but I will try there is a solution it is obvious it is x=y other solution $\displaystyle yln(x)=xln(y)$ that's all I can do for now
Originally Posted by dhiab Exponential equation : Read this thread: http://www.mathhelpforum.com/math-he...stion-3-a.html Thread closed.
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