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Math Help - Graph of trig function

  1. #1
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    Post Graph of trig function

    Graph y = -tan(π/2). What are its vertical asymptotes?

    How would I graph the function?
    Thanks!
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    Quote Originally Posted by live_laugh_luv27 View Post
    Graph y = -tan(π/2). What are its vertical asymptotes?

    How would I graph the function?
    Thanks!
    y=-\tan\left(\frac{n}{2}\right)=\ -\frac{\sin\left(\frac{n}{2}\right)}{\cos\left(\fra  c{n}{2}\right)} and if you know the half angle formulas, which state

    \sin\left(\frac{n}{2}\right)=\pm\sqrt{\frac{1-\cos(n)}{2}}
    \cos\left(\frac{n}{2}\right)=\pm\sqrt{\frac{1+\cos  (n)}{2}}

    Then -\frac{\sin\left(\frac{n}{2}\right)}{\cos\left(\fra  c{n}{2}\right)}=\pm\sqrt{\frac{1-cos(n)}{1+cos(n)}}=\pm\sqrt{\frac{1-cos(n)}{1+cos(n)}*\frac{1-cos(n)}{1-cos(n)}}=\pm\sqrt{\frac{(1-cos(n))^2}{1-cos^2(n)}}

    =\pm\sqrt{\frac{(1-cos(n))^2}{sin^2(n)}}=\frac{1-cos(n)}{sin(n)}

    Now finding your asymptotes should be easy (sin(n)=0) and graphing this by hand, well I would graph the numerator and then the denominator, and then divide the corresponding y values point by point for an accurate sketch




    as theemptyset has just pointed out, seems as though i may have misinterpretted that pi for an n, making this wrong and yeah... sorry for that
    Last edited by artvandalay11; June 1st 2009 at 07:03 PM. Reason: wrong problem
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  3. #3
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    Quote Originally Posted by live_laugh_luv27 View Post
    Graph y = -tan(π/2). What are its vertical asymptotes?

    How would I graph the function?
    Thanks!
    I am going to assume that you mean

    y=-\tan\left( \frac{\pi}{2} {\color{red}x}\right)

    The negative flips the graph of the tangent, and the \frac{\pi}{2} compresses the peroid of the function to (-1,1)

    So the graph is

    Graph of trig function-capture.jpeg
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