A triangle has vertices A(-2,1,3), B(7,8,-4), and C(5,0,2). Determine the area of triangle ABC.
Vector AB = B-A = [9,7,-7]
Vector AC = C-A = [7, -1, -1]
Area of triangle = (ACxAB)/2
I end up getting vector [-14, -40, -40] and the magnitude is not the correct answer of 35.9 square units. Can someone help?
Hello, millerst!
A small error . . .
A triangle has vertices A(-2,1,3), B(7,8,-4), and C(5,0,2).
Determine the area of triangle ABC.
Area of triangle . . . . Correct so far!
I end up getting vector . ← Here!
The correct answer is 35.9 unitsē.
Can someone help?
The cross product is: .
Edit: Too fast for me, spec!
.