# Thread: can some one help me solve for x?

1. ## can some one help me solve for x?

I have been trying to solve this problem for a while now. It's really annoying me. Please walk me through this one.

How do i solve this algebra problem? 1/3x +1/x+1 = 1/(x^2+x)?

2. Originally Posted by sgonzalez90
I have been trying to solve this problem for a while now. It's really annoying me. Please walk me through this one.

How do i solve this algebra problem? 1/3x +1/x+1 = 1/(x^2+x)?
It's really hard to read this.
Do you mean

$\displaystyle \frac{1}{3x} + \frac{1}{x+1} = \frac{1}{x^2+x}$ ?

If so multiply by x^2+x

$\displaystyle \frac{x^2+x}{3x} + \frac{x^2+x}{x+1} = 1$

$\displaystyle \frac{x^2+x}{3x} + \frac{x(x+1)}{x+1} = 1$

$\displaystyle \frac{x^2+x}{3x} + x = 1$

$\displaystyle \frac{x^2}{3x}+\frac{x}{3x} + x = 1$

$\displaystyle \frac{x}{3}+\frac{1}{3} + x = 1$

did you mean $\displaystyle \frac{1}{3}x+\frac{1}{x}+1 = \frac{1}{x^2+x}$ ?

multiply by x^2+x

$\displaystyle \frac{1}{3}x*(x^2+x)+\frac{x^2+x}{x}+x^2+x = 1$

$\displaystyle \frac{1}{3}x*(x^2+x)+\frac{x(x+1)}{x}+x^2+x = 1$

$\displaystyle \frac{1}{3}x*(x^2+x)+x+1+x^2+x = 1$
...

Rapha

3. Originally Posted by Rapha
It's really hard to read this.
Do you mean

$\displaystyle \frac{1}{3x} + \frac{1}{x+1} = \frac{1}{x^2+x}$ ?

If so multiply by x^2+x

$\displaystyle \frac{x^2+x}{3x} + \frac{x^2+x}{x+1} = 1$

$\displaystyle \frac{x^2+x}{3x} + \frac{x(x+1)}{x+1} = 1$

$\displaystyle \frac{x^2+x}{3x} + x = 1$

$\displaystyle \frac{x^2}{3x}+\frac{x}{3x} + x = 1$

$\displaystyle \frac{x}{3}+\frac{1}{3} + x = 1$

did you mean $\displaystyle \frac{1}{3}x+\frac{1}{x}+1 = \frac{1}{x^2+x}$ ?

multiply by x^2+x

$\displaystyle \frac{1}{3}x*(x^2+x)+\frac{x^2+x}{x}+x^2+x = 1$

$\displaystyle \frac{1}{3}x*(x^2+x)+\frac{x(x+1)}{x}+x^2+x = 1$

$\displaystyle \frac{1}{3}x*(x^2+x)+x+1+x^2+x = 1$
...

Rapha
the first one and I got 1/2

4. Originally Posted by sgonzalez90
the first one and I got 1/2
Same here, buddy.