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Math Help - can some one help me solve for x?

  1. #1
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    can some one help me solve for x?

    I have been trying to solve this problem for a while now. It's really annoying me. Please walk me through this one.

    How do i solve this algebra problem? 1/3x +1/x+1 = 1/(x^2+x)?
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  2. #2
    Senior Member
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    Quote Originally Posted by sgonzalez90 View Post
    I have been trying to solve this problem for a while now. It's really annoying me. Please walk me through this one.

    How do i solve this algebra problem? 1/3x +1/x+1 = 1/(x^2+x)?
    It's really hard to read this.
    Do you mean

    \frac{1}{3x} + \frac{1}{x+1} = \frac{1}{x^2+x} ?

    If so multiply by x^2+x

    \frac{x^2+x}{3x} + \frac{x^2+x}{x+1} = 1

    \frac{x^2+x}{3x} + \frac{x(x+1)}{x+1} = 1

    \frac{x^2+x}{3x} + x = 1

    \frac{x^2}{3x}+\frac{x}{3x} + x = 1

    \frac{x}{3}+\frac{1}{3} + x = 1

    did you mean \frac{1}{3}x+\frac{1}{x}+1 = \frac{1}{x^2+x} ?

    multiply by x^2+x

    \frac{1}{3}x*(x^2+x)+\frac{x^2+x}{x}+x^2+x = 1

    \frac{1}{3}x*(x^2+x)+\frac{x(x+1)}{x}+x^2+x = 1

    \frac{1}{3}x*(x^2+x)+x+1+x^2+x = 1
    ...

    Rapha
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  3. #3
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    Quote Originally Posted by Rapha View Post
    It's really hard to read this.
    Do you mean

    \frac{1}{3x} + \frac{1}{x+1} = \frac{1}{x^2+x} ?

    If so multiply by x^2+x

    \frac{x^2+x}{3x} + \frac{x^2+x}{x+1} = 1

    \frac{x^2+x}{3x} + \frac{x(x+1)}{x+1} = 1

    \frac{x^2+x}{3x} + x = 1

    \frac{x^2}{3x}+\frac{x}{3x} + x = 1

    \frac{x}{3}+\frac{1}{3} + x = 1

    did you mean \frac{1}{3}x+\frac{1}{x}+1 = \frac{1}{x^2+x} ?

    multiply by x^2+x

    \frac{1}{3}x*(x^2+x)+\frac{x^2+x}{x}+x^2+x = 1

    \frac{1}{3}x*(x^2+x)+\frac{x(x+1)}{x}+x^2+x = 1

    \frac{1}{3}x*(x^2+x)+x+1+x^2+x = 1
    ...

    Rapha
    the first one and I got 1/2
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  4. #4
    Senior Member
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    Quote Originally Posted by sgonzalez90 View Post
    the first one and I got 1/2
    Same here, buddy.
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