in the function f(x) = 1 + 1/x, when x= 0 does f(x) remain real? apparently not (seeing the graph), but why? shouldnt f(x) = 1? is my graph wrong?

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- May 31st 2009, 11:53 PMthe kopitereal function?
in the function f(x) = 1 + 1/x, when x= 0 does f(x) remain real? apparently not (seeing the graph), but why? shouldnt f(x) = 1? is my graph wrong?

- June 1st 2009, 12:57 AMmr fantastic
- June 1st 2009, 01:30 AMthe kopite
which means that f(x)= 1 + (1/x) cannot be real for x = 0? that was the question.

- June 1st 2009, 01:32 AMmr fantastic
- June 1st 2009, 01:39 AMthe kopite
?

- June 1st 2009, 06:15 AMShowcase_22
Suppose

This gives

Hence there does not exist an such that .

EDIT: this is quite apparent since for which cannot happen (since it leads to the same contradiction as before). - June 1st 2009, 05:46 PMNerdfighter
Basically, you can never divide by zero. is undefined. It simply does not exist, and there is nothing wrong with your graph.