How do you find the maximum of r and any zeros? My math teacher did not explain this well at all..
r= 8(√3-2sinΘ)
r = 0: Solve $\displaystyle 0 = \sqrt{3} - 2 \sin \theta$.
Maximum value of r: Get it by inspection - Draw a graph of $\displaystyle r = \sqrt{3} - 2 \sin \theta$. Note that $\displaystyle r$ is the vertical axis and $\displaystyle \theta$ is the horizontal axis. Note: This is not the same as the the graph of the polar curve (which is drawn on a set of xy-coordinate axes).