How do you find the maximum of r and any zeros? My math teacher did not explain this well at all..
r= 8(√3-2sinΘ)
I am sure that you would agree that r = 0 when (rad3 - 2sin(theta))= 0 yes?
So:
rad[3] - 2sin[theta] = 0
2sin[th] = rad[3]
sin[th] = (rad[3])/2
So now you need the sin inverse of rad three over two. Keep in mind that there are two correct answers or you can use pi2k.
How do you find the maximum of r and any zeros? My math teacher did not explain this well at all..
r= 8(√3-2sinΘ)
r = 0: Solve .
Maximum value of r: Get it by inspection - Draw a graph of . Note that is the vertical axis and is the horizontal axis. Note: This is not the same as the the graph of the polar curve (which is drawn on a set of xy-coordinate axes).