How do you find the maximum of r and any zeros? My math teacher did not explain this well at all..

r= 8(√3-2sinΘ)

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- May 30th 2009, 10:15 AMjumpman23Finding maximum r-values of ploar equations
How do you find the maximum of r and any zeros? My math teacher did not explain this well at all..

r= 8(√3-2sinΘ) - May 30th 2009, 01:31 PMpberardi
I am sure that you would agree that r = 0 when (rad3 - 2sin(theta))= 0 yes?

So:

rad[3] - 2sin[theta] = 0

2sin[th] = rad[3]

sin[th] = (rad[3])/2

So now you need the sin inverse of rad three over two. Keep in mind that there are two correct answers or you can use pi2k. - May 30th 2009, 02:53 PMmr fantastic
r = 0: Solve $\displaystyle 0 = \sqrt{3} - 2 \sin \theta$.

Maximum value of r: Get it by inspection - Draw a graph of $\displaystyle r = \sqrt{3} - 2 \sin \theta$. Note that $\displaystyle r$ is the vertical axis and $\displaystyle \theta$ is the horizontal axis.**Note: This is not the same as the the graph of the polar curve (which is drawn on a set of xy-coordinate axes).** - May 31st 2009, 07:49 PMpickslides
for $\displaystyle y = Asin(x)+B$

$\displaystyle y_{min} = B+A$

$\displaystyle y_{max} = B-A$

expand your equation and it will be in this form.