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Math Help - Slope (parallel and perpendicular)

  1. #1
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    Slope (parallel and perpendicular)

    Hi,

    I'm yet again having trouble grasping this concept. I've been given the point: (7/8, 3/4) and the equation 5x + 3y = 0. Now from this information I need to find equations of lines that are :
    (a) parallel to the given line
    and then
    (b) perpendicular to the given line


    How can one approach this problem and solve down for the equations of the lines?

    Thank you yet again.
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  2. #2
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    Quote Originally Posted by hemi View Post
    I've been given the point: (7/8, 3/4) and the equation 5x + 3y = 0. Now from this information I need to find equations of lines that are : (a) parallel to the given line
    and then
    (b) perpendicular to the given line
    Parallel lines have the same slope.
    So any line parallel to the given line looks like 5x+3y=C.

    Perpendicular lines have slopes that multiply to -1
    So any line perpendicular to the given line looks like 3x-5y=C.

    To find C simply use the given point.
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  3. #3
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    Quote Originally Posted by Plato View Post
    Parallel lines have the same slope.
    So any line parallel to the given line looks like 5x+3y=C.

    Perpendicular lines have slopes that multiply to -1
    So any line perpendicular to the given line looks like 3x-5y=C.

    To find C simply use the given point.


    So:
    5(7/8)+3(3/4)=6.625

    and:
    3(7/8)-5(3/4)=-1.125

    But this answer does not give me an equation of a line (if I did it correctly)? How can I write this as such as an equation of a line. Thanks a lot for your help Plato.
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  4. #4
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    Quote Originally Posted by hemi View Post
    So:
    5(7/8)+3(3/4)=6.625

    and:
    3(7/8)-5(3/4)=-1.125

    But this answer does not give me an equation of a line (if I did it correctly)? How can I write this as such as an equation of a line.
    5x+3y=\frac{53}{8}


    and:
    3x-5y=\frac{-9}{8}
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  5. #5
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    Thank you Plato.
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