Log10(x)=ylog10(3)+1

express y in terms of x

help?

explaination needed though

Printable View

- May 20th 2009, 08:44 AMaimeemcdonaldLogs
Log10(x)=ylog10(3)+1

express y in terms of x

help?

explaination needed though - May 20th 2009, 10:35 AMearboth
$\displaystyle \log_{10}(x)=y \cdot \log_{10}(3) + 1$

$\displaystyle \log_{10}(x)-1=y \cdot \log_{10}(3) $

$\displaystyle \log_{10}\left(\dfrac x{10}\right)=y \cdot \log_{10}(3) $

$\displaystyle \dfrac{\log_{10}\left(\dfrac x{10}\right)}{\log_{10}(3)}=y $

which can be simplified to:

$\displaystyle y = \log_3\left(\dfrac x{10} \right)$