Hello,
The problem is that it's arctan 1/(-1), because it's 1+(-1)i
so this gives the angle -pi/4
I have to write 1-i in exponential form. Please check my answer. If it is okay, yeah! If it is incorrect, could you help me?
r=sq.rt.(1^2 - (i)^2)
r=sq.rt.(1 + 1)
r=sq.rt.(2)
arctan 1/1 = pi/4 (45 degrees) cos pi/4 = .707, sin pi/4 = .707
.707/.707 =1
My answer: sq.rt.2(e^ipi/4)
Is this correct?