by putting $\displaystyle t = tan\frac{\theta}{2}$, find the general solution of the equation
$\displaystyle 3cos\theta + 4sin\theta = 3 - tan\frac{\theta}{2}$
OK i've worked it out to
$\displaystyle t(t-3)(t-3)$
$\displaystyle \therefore t=0, t=3$
but not sure what to do from here.
I also know the general solution for tan is $\displaystyle \theta=\pi n + \alpha$