I'm having trouble with missing factors, here's an example: 9x(2+x^5)^(1/3)= [blank](2+x^5)^(1/3)(2x) any help solving these is appreciated
Follow Math Help Forum on Facebook and Google+
Well, you've got $\displaystyle (2+x^5)^{1/3}$on both sides of the= sign. So you can forget about thaose for a minute and divide them out. Then what do ya got left? 9x=(?)2x In other words, what do you have to multiply 2 by to get nine?
$\displaystyle \frac{9}{2}$ is the missing factor!
View Tag Cloud