Suppose p varies directly as the cube of x, and inversely with y. If p=5/8 when x=4 and y=10, find p when x=2 and y=16

How do you set up the steps?

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- May 17th 2009, 04:31 PMreuger_Rational Functions?
Suppose p varies directly as the cube of x, and inversely with y. If p=5/8 when x=4 and y=10, find p when x=2 and y=16

How do you set up the steps? - May 17th 2009, 04:43 PMJen
When P varies directly with x, it means, for some constant k.

If P varies directly with the cube of x then,

When P varies inversely with y it means,

Now if you use the initial conditions provided you should be able to solve for the constants - May 17th 2009, 04:51 PMreuger_thanks
- May 17th 2009, 05:02 PMJen
No Problem. :D