Here is the problem:
An airplane is flying on bearing of 194° at 460 mph. Find component form of velocity of airplane.
Here is what I have done...is it correct?
194° => 166°
v = (460cos166°)i + (460sin166°)j
v = <460cos166°, 460sin166°>
v = <-446.3, 111.29>
Thanks!
The way I learned it in navigation 0° = North, 90° = East, 180° = South, and 270° = West. So 194° is 14° to the west of south. Now in the Cartesian plane, the terminal side would be in Quadrant III (look at earboth's diagram). The negative y-axis is now 270°, so 14° to the west of this axis means you subtract 14° from 270°, getting 256°.
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