# Math Help - Domain of a function

1. ## Domain of a function

f(x,y) = Sqrt(y-x^2)/(x^2+(y-1)^2) Find and graph the domain of the function

f(x,y) = Sqrt(y-x^2)/(x^2+(y-1)^2) Find and graph the domain of the function
The domain of $\sqrt{x}$ is all $x\ge 0$ so you must have $y- x^2\ge 0$. Graph $y= x^2$. $y\ge x^2$ for all (x,y) below that graph. The domain of 1/x is all x not equal to 0. The domain of $\frac{1}{x^2+(y-2)^2}$ is all (x, y) except the single point where that denominator is 0. The domain of f is the points that are in both of those domains.

Find and graph the domain of: . $f(x,y) \;=\; \sqrt{\frac{y-x^2}{x^2+(y-1)^2}}$

The denominator is always positive except at (0,1) where the function is undefined.

The numerator must be nonnegative: . $y - x^2 \:\geq \:0 \quad\Rightarrow\quad y \:\geq \:x^2$
. . This is the set of points on and above the parabola: $y \,=\,x^2$

The region looks like this:
Code:
:::::::::::|:::::::::::
*::::::::::|::::::::::*
::::::::::|::::::::::
*:::::::::|:::::::::*
*::::::::o::::::::*
*::::::|::::::*
*:::|:::*
- - - - - - * - - - - - -
|
where there is a "hole" at (0,1).