Solve for X: 3^(4x) greater-than or equal to 27
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Originally Posted by oneway1225 Solve for X: 3^(4x) greater-than or equal to 27 $\displaystyle 3^{4x} \ge 3^3$ can you finish?
no I'm not sure what to do next
Originally Posted by oneway1225 no I'm not sure what to do next if $\displaystyle 3^{4x} \ge 3^3$ , then wouldn't it make sense that $\displaystyle 4x \ge 3$ ?
x=3/4 because 3^3=27 Take natural log of both sides. x>(1/4)*(ln27)/(ln3)
Originally Posted by Tim28 x=3/4 because 3^3=27 Take natural log of both sides. x>(1/4)*(ln27)/(ln3) Actually, $\displaystyle x \geq \frac{3}{4}$.
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