Solve the logarithmic equation
Log(sub 9)x = 3/2
I have the equation as far as
Log 9*3/2 = x
but I am unsure if this is correct or not. Please help? Thanks!
$\displaystyle \log_a b \Longleftrightarrow \frac {log_c b}{log_c a}$
$\displaystyle \log_9 x = \frac {3}{2}$
$\displaystyle \log_9 x = \frac {logx}{log9}$
$\displaystyle \frac {logx}{log9} = \frac {3}{2}$
Solve for x. Please note that logarithms should be part of the Algebrea/Pre-Algebra category, and not pre-calculus.