Originally Posted by

**chrozer** the course and ground speed of a plare are 70 degree and 400 miles per hour respectively. There is a 60 mph wind blowing from the south. find the approximate direction and air speed of the plane.

This is how I learned how to solve it with vectors:

$\displaystyle v_1 = 400 \langle \cos {70}, \sin {70} \rangle$

$\displaystyle v_1 = \langle 253.33, 309.56 \rangle$

Would the vector for the wind be:

$\displaystyle v_2 = 60 \langle \cos {270}, \sin {270} \rangle$ ?

I'm confused on the part of the question that says the wind is blowing from the south. Help?

Then you would just add the two vectors and find the resultant for the speed of the airplane right? How would you find the direction of the airplane?