Originally Posted by

**nikkkk** Suppose on Jan 1, 1997 Dave invested $2,000 into a bank account at 5% interest compounded continuously. Let y(t) be the value of Dave's investment after t years.

Also on Jan 1, 1997 John decides to invest. He put $2,500 into an account at

3% interest compounded monthly. Let g(t) be the value of John's investment after t years.

**To the nearest tenth, at what time t is the value of both accounts the same?**

So I know you set ;

2000e^(.03)t = 2,500 (1 + .03/12) ^ (12)t

How do you go about solving?