If I have a relation in Vertex form, how do I make it into standard form?
y = a(x-h)^2 + k into y = ax^2 + bx +c
Example questions:
a) y = 5(x+3)^2 -2
b) y = 2x(5-2x)+7
I'm not exactly looking for the answers, I just want to understand HOW to solve these.
Please help!
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heres my solution to question a, if you could advise me that would be much appreciated!
y = 5(x+3)^2 -2
= 5(x^2+9x-9)-2
= 5(x^2+9x)-2+9
= 5x^2 + 9x + 7
Sorry, I didn't realize you hadn't spotted what you are trying to do.
All you are up do in this sort of thing is expanding the quadratic into its separate terms.
In this case just multiply it out:
y = 2x(5-2x)+7
y = 10x - 4x^2 + 7
y = -4x^2 + 10x + 7
This is far easier than taking y = ax^2 + bx + c and going to y = a(x - h)^2 + k. All you need to do is expand out all the terms and simplify.
-Dan