If I have a relation in Vertex form, how do I make it into standard form?
y = a(x-h)^2 + k into y = ax^2 + bx +c
a) y = 5(x+3)^2 -2
b) y = 2x(5-2x)+7
I'm not exactly looking for the answers, I just want to understand HOW to solve these.
heres my solution to question a, if you could advise me that would be much appreciated!
y = 5(x+3)^2 -2
= 5x^2 + 9x + 7
All you are up do in this sort of thing is expanding the quadratic into its separate terms.
In this case just multiply it out:
y = 2x(5-2x)+7
y = 10x - 4x^2 + 7
y = -4x^2 + 10x + 7
This is far easier than taking y = ax^2 + bx + c and going to y = a(x - h)^2 + k. All you need to do is expand out all the terms and simplify.