Thread: Solve the Following Trigonometric Equation

Hey, in pre-cal we're going over some of the stuff we learned this semester. Unfortunately for me, I have forgotten a bit of it:

So, here's the problem:
Solve the equation:
sin2x + cos3x = 0 for [0, 2pi)

I wish I could just graph it, but I have to do it algebraically and show all work. Any clues as to how to approach this would be appreciated

Thanks

Originally Posted by ayoYNr

Hey, in pre-cal we're going over some of the stuff we learned this semester. Unfortunately for me, I have forgotten a bit of it:

So, here's the problem:
Solve the equation:
sin2x + cos3x = 0 for [0, 2pi)

I wish I could just graph it, but I have to do it algebraically and show all work. Any clues as to how to approach this would be appreciated

Thanks

first task ... you'll need to expand and

... that's done.

... keep going

Ok, so now I have:

2sinxcosx + cos(2x)cosx - sin(2x)sinx

Where do I go from here?

(Sorry, ignore this post)

Originally Posted by ayoYNr

Ok, so now I have:

2sinxcosx + cos(2x)cosx - sin(2x)sinx

Where do I go from here?

... should be straightforward to solve for x

... you'll need to use the quadratic formula to solve for