ABS(2x + y) - ABS(x + 3y) = 8

ABS = absolute value

I need to know where to start

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- May 4th 2009, 02:35 PMmathprobAbsolute value graph
ABS(2x + y) - ABS(x + 3y) = 8

ABS = absolute value

I need to know where to start - May 4th 2009, 03:30 PMVonNemo19

This is what we wish to solve.

We first must recognize that. So, knowing this, can you finish up?*or* - May 4th 2009, 03:43 PMmathprob
- May 4th 2009, 04:31 PMVonNemo19
When dealing with absolute value, you have to be aware of the folling fact-that So, therefore can have 2 different values, but the corresponding value of , or will have only one. So knowing that....

We've got to set up different possibilities for the given expressions.

and .

So, with this, can you take it from here? - May 4th 2009, 04:39 PMVonNemo19
- May 4th 2009, 04:45 PMmathprob
i dont really know what you want me to do? what do i do after i get +- ?

what does the square root formula have to do with this - May 4th 2009, 04:51 PMVonNemo19
Solve for y for the different possibilities and then plot your graph.

Pythagoras has nothing to do with this. I was showing my brother how to type in math code.(Wink) - May 4th 2009, 04:53 PMmathprob
- May 4th 2009, 05:11 PMVonNemo19
It stays right were it is. you leave everything the same but the two expressions in the inequality signs

- May 4th 2009, 05:16 PMmathprob