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Math Help - precal 5.1 to 5.3

  1. #1
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    precal 5.1 to 5.3

    solve over the requested interval.

    how do you solve these?

    sin2x+2tan2x=0 (interval = negative infinity to positive infinity)

    2sin^2(3x)-cos3x-1=0 same interval as the first one
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  2. #2
    MHF Contributor
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    Quote Originally Posted by smyleeface17 View Post
    sin2x+2tan2x=0 (interval = negative infinity to positive infinity)
    Convert the tangent to sines and cosines. Multiply through by cos(2x) to clear the denominator. Factor, and solve the resulting trig equations.

    Quote Originally Posted by smyleeface17 View Post
    2sin^2(3x)-cos3x-1=0 same interval as the first one
    Convert the squared sine to 1 - cos^2(3x). Then factor the resulting quadratic, and solve the factors.

    If you get stuck, please reply showing how far you have gotten. Thank you!
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