Hey guys I have a question I've been stuck on. The problem says

Find the equation of the parabola with the given properties.

Vertex(1,3); vertical axis of symmetry; containing the point(-1,19)

I can't find this in my book anywhere.

I also have on that says Find the center, foci, and asymptotes of the hyperbola.

7x^2 - y^2 - 42x + 8y - 65 = 0

I think I have the completing the square down. I'm not sure though

I get stuck at this part

7(x^2 - 6x) - 1(y^2 - 8y) = -65

I'm stuck what to do with the completing the square after that. After that I'm not sure on how to find the center, asymptotes and foci.

And I hope I'm not asking to much. But I have this question to. I'm not sure where to start.

Find the equation of the hyperbola satisfying the given conditions.

Vertices: (-6,4) and (8,4); asymptotes y = 2x + 8 and y = -2x + 0

Thanks for any help, steps, or answers guys. I appreciate a lot.