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Math Help - sequence question

  1. #1
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    sequence question

    The general term of a series is tn= pie(3/11)^n+1, how many terms must be added to reach a sum that is greater than 0.32

    the only problem is,when I substitue 1 in for n...I already get a sum bigger than 0.32,the question is out of 4 marks,so I know thats not the answer....I'm stumped
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  2. #2
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    Quote Originally Posted by dan123 View Post
    The general term of a series is tn= pie(3/11)^n+1, how many terms must be added to reach a sum that is greater than 0.32

    the only problem is,when I substitue 1 in for n...I already get a sum bigger than 0.32,the question is out of 4 marks,so I know thats not the answer....I'm stumped
    You need the sum of the series rather than the general term of a series:

    Did you mean t_n = (\frac{3\pi}{11})^{n+1} or

    t_n = (\frac{3\pi}{11})^n +1
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  3. #3
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    the pie is outside of the bracket,with the (3/11) inside the bracket so pie(3/11) then yeah the n+1 is an exponent
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  4. #4
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    I read the question as S_n  = \sum\limits_{k = 1}^n {\pi \left( {\frac{3}<br />
{{11}}} \right)^{k + 1} } and S_n>0.32 if n\ge 5.
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