3^x = 4x + 15

Here's the farthest I can get:

log(3^x) = log(4x + 15)

xlog(3) = log(4x + 15)

x = log(4x + 15)/log(3)

Is graphing and finding the intersection point the only way to solve this?

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- April 26th 2009, 10:26 AMPhireUnsolvable problem?
3^x = 4x + 15

Here's the farthest I can get:

log(3^x) = log(4x + 15)

xlog(3) = log(4x + 15)

x = log(4x + 15)/log(3)

Is graphing and finding the intersection point the only way to solve this? - April 26th 2009, 10:43 AMstapel
To my knowledge, this equation cannot be solved algebraically. You will have to use other methods. Sorry! (Blush)

- April 26th 2009, 11:06 AMe^(i*pi)