So theres this question in my textbook:..
Find the point of intersection between the function y= (3/((3x-4)^2)) + 6
I know you begin with
x = (3/((3x-4)^2)) + 6
x-6 = (3/((3x-4)^2))
√ (x-6)(3x-4)= √ 3
but then i just keep going round in circles and can never get the x on its own.
any help would be greatly appreciated=]