So theres this question in my textbook:..

Find the point of intersection between the function y= (3/((3x-4)^2)) + 6

I know you begin with

x = (3/((3x-4)^2)) + 6

x-6 = (3/((3x-4)^2))

√ (x-6)(3x-4)= √ 3

but then i just keep going round in circles and can never get the x on its own.

any help would be greatly appreciated=]