[(cos(2ɵ)-cos(4ɵ))/(cos(2ɵ)+cos(4ɵ))] - tanɵtan(3ɵ)=0

thanks guys

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- April 23rd 2009, 10:04 PMjohnnyc418establish the identity
[(cos(2ɵ)-cos(4ɵ))/(cos(2ɵ)+cos(4ɵ))] - tanɵtan(3ɵ)=0

thanks guys - April 24th 2009, 03:56 AMSoroban
Hello, Johnny!

We need two sum-to-product identities:

. .

. .

Quote:

The fraction is: . .

Then the problem becomes: .