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- April 23rd 2009, 09:00 AMSarahGrSolve: tan2x + tan x = 0
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- April 23rd 2009, 09:09 AMrunning-gag
Hi

You can use the trig identity and factor - April 23rd 2009, 11:58 AMmasters
- April 23rd 2009, 12:18 PMrunning-gag
can also lead to

- April 23rd 2009, 12:51 PMe^(i*pi)
- April 23rd 2009, 12:54 PMrunning-gag
- April 23rd 2009, 03:07 PMSarahGr
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- February 5th 2013, 06:41 AMscottsophieRe: Solve: tan2x + tan x = 0
overall, with tan(x)=0, tan(x)=√3, tan(x)=-√3

between 0≤x≤360: x= 0°, 60°, 120°, 180°, 240°, 300°, 360° - February 5th 2013, 07:34 AMPetrusRe: Solve: tan2x + tan x = 0
- February 5th 2013, 07:55 AMscottsophieRe: Solve: tan2x + tan x = 0
you have (tan2x/1-tan

^{2}x) + tanx = 0

You find a common denominator of 1-tan^{2}x

this gives you: tan2x + (tanx)(1-tan^{2}x) = 0

(this equation is all over '1-tan^{2}x', but you can get rid of it by moving it to the other side of the '=' sign, and multiplying this by the 0).

You then expand the brackets to get: tan2x + tanx - tan^{3}x = 0

You then simplify this to get: tan3x + tanx = 0

Hope this helps. - February 5th 2013, 08:58 AMPetrusRe: Solve: tan2x + tan x = 0
Thanks:) got it:) ii thought so.. but was not 100% it was correct:)