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Math Help - Properties of Logarithms

  1. #1
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    Question Properties of Logarithms

    Hi, can someone please help me figure this problem out?

    <br />
2^{log_{2}5} - 3log_{5}(^{3}\sqrt{5})<br />

    Thanks for the help!
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  2. #2
    Junior Member woof's Avatar
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    Hint: logs and exponents "undo" each other

    log_b\ (b^{(stuff)})=stuff and also b^{log_b(stuff)}=stuff

    The key is that you need the bases the same.
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  3. #3
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    Question

    I kind of understand what you're saying, but I'm not really getting the whole problem in general.

    So, 2^{log_{2}5} equals 5?
    What happens with 3log_{5}(^{3}\sqrt{5})<br />
?
    Last edited by juicysharpie; April 22nd 2009 at 12:31 AM.
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  4. #4
    Junior Member woof's Avatar
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    Quote Originally Posted by juicysharpie View Post
    I kind of understand what you're saying, but I'm not really getting the whole problem in general.

    So, 2^{log_{2}5} equals 5?
    Yes.

    What happens with 3log_{5}(^{3}\sqrt{5})<br />
?
    This one is more complicated.

    Is it more clear if you write it this way: 3\ [\ log_{5}(5^{1/3})\ ], so ultimately it becomes 1, after multiplying the 3 through?
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  5. #5
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    Oh, I see! Thanks for the help! I'm studying for a test, but I haven't done this stuff in awhile, so I'm a little rusty. Thanks again!
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  6. #6
    Junior Member woof's Avatar
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    You're Welcome!! Good luck on the test!
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