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Math Help - Simplifying Trig Expressions

  1. #1
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    Exclamation Simplifying Trig Expressions

    cot^2x - cot^2x(cos^2x)

    secx - (cosx/1+sinx)
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  2. #2
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    Quote Originally Posted by nichole23 View Post
    cot^2x - cot^2x(cos^2x)

    secx - (cosx/1+sinx)
    Hi nichole23,

    \cot^2 x-\cot^2 x(\cos^2 x)=\cot^2 x(1-\cos^2 x)=\frac{\cos^2 x}{\sin^2 x}\left(\sin^2 x\right)=\cos^2 x

    -----------------------------------------------------------------------

    \sec x-\frac{\cos x}{1+\sin x}=

    \frac{1}{\cos x}-\frac{\cos x}{1+\sin x}=

    \frac{1+\sin x-\cos^2 x}{\cos x(1+\sin x)}=

    \frac{1-\cos^2 x+\sin x}{\cos x(1+\sin x)}=

    \frac{\sin^2 x+\sin x}{\cos x(1+\sin x)}=

    \frac{\sin x(\sin x+1)}{\cos x(1+\sin x)}=

    \frac{\sin x}{\cos x}=

    \tan x
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  3. #3
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    Quote Originally Posted by nichole23 View Post
    cot^2x - cot^2x(cos^2x)

    secx - (cosx/1+sinx)
    Here's the first one:

    cot^2 x - cot^2x(cos^2 x)

    cot^2 x(1- cos^2 x)

    cot^2 x(sin^2 x)

    You should be able to complete the rest from here?
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  4. #4
    Super Member craig's Avatar
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    Got beaten to it
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