Given (y-2)^2 - X^2/4=1, do the following

a) write the equation in general form:

my answer:

(y-2)^2 - X^2/4=4

4(y-2)^2-1(x)^2=4

4(y^2-4y+4) -1(x^2+x)=4

4y^2-16y+16-(x^2+x)= 4

4y^2-16y+16-X^2+x=4

-x^2+4y^2+x-16y-16=4

-x^2+4y^2+x-16y-20=0

general form:

-x^2+4y^2+x-16y-20=0

How do I locate the vertices and center of this hyperbola??

thanks for your help!!!