$\displaystyle 5^{2x} -130^x + 25 = 0$

This is what I tried:

$\displaystyle 5(1^{2x}-26^x + 5) = 0$

$\displaystyle 5(1^{2x}-26 * 1^x + 5) = 0$

$\displaystyle 1^x = y$

$\displaystyle 5(y^2-26y+5) = 0$

Solving the above quadratic doesn't give me the right answers, unless I solved it wrong, but I don't think I did. What did I do wrong?