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Math Help - what is the pattern?

  1. #1
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    what is the pattern?

    t1=0, find the first few terms tn=1/tn-1+2, what is the pattern?
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  2. #2
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    Hello, nithujaa!

    Given: . t_1=0,\;\;t_n\:=\:\frac{1}{t_{n-1}+2}

    Find the first few terms. .What is the pattern?

    \begin{array}{ccccccc} t_1 &=& 0 \\ t_2 &=& \frac{1}{0+2} &=& \frac{1}{2} \\ \\[-4mm] t_3 &=& \frac{1}{\frac{1}{2} + 2} &=& \frac{1}{\frac{5}{2}} &=& \frac{2}{5} \\ \\[-4mm] t_4 &=& \frac{1}{\frac{2}{5}+2} &=& \frac{1}{\frac{12}{5}} &=& \frac{5}{12} \\ \\[-4mm] t_5 &=& \frac{1}{\frac{5}{12}+2} &=& \frac{1}{\frac{29}{12}} &=& \frac{12}{29} \end{array}


    The fractions are: . \frac{0}{1},\; \frac{1}{2}, \;\frac{2}{5},\; \frac{5}{12},\; \frac{12}{29},\; \frac{29}{70},\; \frac{70}{169},\; \frac{169}{408},\; \hdots


    The numerators form the sequence: . 0,1,2,5,12,29, 70, 169, 408, \hdots
    The denominators are "one step ahead."

    For the numerators, we have: . a_1 = 0,\;a_2 = 1,\;a_n \:=\:2a_{n-1} + a_{n-2}
    . . Each term is twice the preceding term, plus the second preceding term.


    If you require a "closed form" for the numerators, here it is:

    . . a_n \;=\;\frac{(1+\sqrt{2})^{n-1} - (1-\sqrt{2})^{n-1}}{2\sqrt{2}}

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  3. #3
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    thx..but this question is for data management?..so can i use this method?
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