I think I got it,

would it be discontinuous @ x = 1?

because fory1:

X = -1

solving for 1- (x^2) gives me Y= 0

y2:

X=-1,1

solving for 1+x gives me Y= 0,2

y3:x=1

solving for x^2 + 2 gives me Y = 3

From those values can I say that it is discontinuous at x=1?