I'm having trouble on these questions trying to figure them out but think my work is wrong.
1.Which of the following is equavlant to (2z^3)/(8z^(n-2))
2.Find the range of negative squareroot (36-x^2)
so far I gotten (x+6)=-6 and (x-3)=6 so would it be y:y -6<y<6?
3. Find all solutions for sin^2=3cos^2
so would it be 0, pie/2, 1/3 ?
Thus the answer is neither of the choices. If the question is written as (2z)^3, then the answer is B. If it's 2z^3, then my answer doesn't fit into any.
Divide by on the both sides, you get:
Square root both sides, you get: = sqrt(3) or -sqrt(3)
Therefore the critical angle is pi/3. If you are looking angles between 0 and 2pi, the possible answers are pi/3, 2*pi/3, 4*pi/3, 5*pi/3.
Hope this helps.