convert the rectangular to a polar equation: -8x-3y+5=0 i know that x= r cos theta, as well as other identities convert the polar to a rectangular equation: r= 2/ (4-5 cos theta) i don't even know where to begin here! thanks
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Originally Posted by ss103 convert the rectangular to a polar equation: -8x-3y+5=0 i know that x= r cos theta, as well as other identities Mr F says: Then substitute them into the equation and solve for r. convert the polar to a rectangular equation: r= 2/ (4-5 cos theta) i don't even know where to begin here! thanks . Now square both sides and substitute . Re-arrange into a standard form (looks like it might be a hyperbola).
thanks! but for the first one, i tried to solve it but i dont know how: -8r cos theta - 3r sin theta +5 =0 where do i go now? do i square it?
Originally Posted by ss103 thanks! but for the first one, i tried to solve it but i dont know how: -8r cos theta - 3r sin theta +5 =0 where do i go now? do i square it? => 8r cos theta + 3r sin theta = 5 => r (8 cos theta + 3 sin theta) = 5 etc.
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