I'm having trouble solving this equation

(3,3) to polar and (8,PI) to rectangular.

I know hoe to change it when its in a equation like 4cis5theata, but i don't know how when its in coordinates.

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- Apr 5th 2009, 04:17 PMxian791Rectangular to Polar, Polar to Rectangular
I'm having trouble solving this equation

(3,3) to polar and (8,PI) to rectangular.

I know hoe to change it when its in a equation like 4cis5theata, but i don't know how when its in coordinates. - Apr 5th 2009, 04:44 PMstapel
Um... these aren't actually "equations". Were the instructions really to "solve", or were you maybe supposed to "

**convert the coordinates**"...?

If so, then note that (3, 3) in rectangular means "x = 3 and y = 3". What then is the value of r? (Use the formula they gave you for this.) Since , what must be the value of

The polar coordinates means that r = 8 and . Plug these into the formulas they gave you for x and y. (Wink) - Apr 5th 2009, 04:51 PMxian791
so to double check (3,3)=(3radical2,theta)

and (8,pi)=(-8,0)

Correct? - Apr 6th 2009, 02:33 PMILoveMaths07
Recall that:

(3, 3) is (x, y) ---> Cartesian/Rectangular

We need (r, ) ---> Polar

So

So (3, 3) in Cartesian coordinates is ( , ) in polar coordinates.

Converting rectangular to polar is easier:

x = r cos theta = 8 cos pi = -8.

y = r sin theta = 8 sin pi = 0.

So (8, ) in polar is (-8, 0) in rectangular.

I hope that helps. :)

ILoveMaths07.