Results 1 to 6 of 6

Math Help - Please check my work

  1. #1
    Junior Member
    Joined
    Jul 2007
    Posts
    67
    Awards
    1

    Please check my work

    Can you please check my work

    Can you please tell me where I went wrong becasue my teacher said that answer is 13720
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member
    Joined
    Dec 2008
    From
    Scotland
    Posts
    901
    Quote Originally Posted by supersaiyan View Post
    Can you please check my work

    Can you please tell me where I went wrong becasue my teacher said that answer is 13720
    Let me get this straight.

    You have a function  f(x) = 400e^{\frac{\ln(2.375)}{2}x} ...

    And you have to find out what  f'(10) is?
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by supersaiyan View Post
    Can you please check my work

    Can you please tell me where I went wrong becasue my teacher said that answer is 13720
    Have you asked your teacher?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Junior Member
    Joined
    Jul 2007
    Posts
    67
    Awards
    1
    Yes, i have, he said check your work again
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Junior Member
    Joined
    Jul 2007
    Posts
    67
    Awards
    1
    Quote Originally Posted by Mush View Post
    Let me get this straight.

    You have a function  f(x) = 400e^{\frac{\ln(2.375)}{2}x} ...

    And you have to find out what  f'(10) is?
    Yes
    Follow Math Help Forum on Facebook and Google+

  6. #6
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by supersaiyan View Post
    Can you please check my work

    Can you please tell me where I went wrong becasue my teacher said that answer is 13720
    f(x) = 400 e^{kx} where k = \frac{1}{2} \ln (2.375).

    f'(x) = 400 k e^{kx}.

    f'(10) = 400 k e^{10k}.

    10 k = 5 \ln (2.375) = \ln (2.375)^5 \Rightarrow e^{10k} = 2.375^5.

    So f'(10) = 200 [\ln (2.375)] \, 2.375^5.

    Now use a calculator if a decimal approximation is required.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 4
    Last Post: March 12th 2011, 05:05 AM
  2. Work--please check my work for me
    Posted in the Calculus Forum
    Replies: 3
    Last Post: February 1st 2011, 10:02 AM
  3. Replies: 1
    Last Post: July 21st 2010, 07:02 PM
  4. check my work please
    Posted in the Calculus Forum
    Replies: 1
    Last Post: January 20th 2007, 08:11 PM
  5. can someone check my work thanks!!
    Posted in the Trigonometry Forum
    Replies: 5
    Last Post: January 3rd 2007, 11:58 AM

Search Tags


/mathhelpforum @mathhelpforum