Please check my work

**supersaiyan** · March 30th 2009, 01:54 PM

Can you please check my work

Can you please tell me where I went wrong becasue my teacher said that answer is 13720

**Mush** · March 30th 2009, 02:23 PM

Originally Posted by supersaiyan

Can you please check my work

Can you please tell me where I went wrong becasue my teacher said that answer is 13720

Let me get this straight.

You have a function $f(x) = 400e^{\frac{\ln(2.375)}{2}x}$ ...

And you have to find out what $f'(10)$ is?

**mr fantastic** · March 30th 2009, 10:19 PM

Originally Posted by supersaiyan

Can you please check my work

Can you please tell me where I went wrong becasue my teacher said that answer is 13720

Have you asked your teacher?

**supersaiyan** · March 31st 2009, 01:53 PM

Yes, i have, he said check your work again

**supersaiyan** · March 31st 2009, 01:54 PM

Originally Posted by Mush

Let me get this straight.

You have a function $f(x) = 400e^{\frac{\ln(2.375)}{2}x}$ ...

And you have to find out what $f'(10)$ is?

Yes

**mr fantastic** · April 2nd 2009, 08:10 PM

Originally Posted by supersaiyan

Can you please check my work

Can you please tell me where I went wrong becasue my teacher said that answer is 13720

$f(x) = 400 e^{kx}$ where $k = \frac{1}{2} \ln (2.375)$ .

$f'(x) = 400 k e^{kx}$ .

$f'(10) = 400 k e^{10k}$ .

$10 k = 5 \ln (2.375) = \ln (2.375)^5 \Rightarrow e^{10k} = 2.375^5$ .

So $f'(10) = 200 [\ln (2.375)] \, 2.375^5$ .

Now use a calculator if a decimal approximation is required.

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