# Math Help - conversion from cartesian to parametric form

1. ## conversion from cartesian to parametric form

hi all,

given the implicit equation $x^2+x+1-y^2 = 0$, how can i find the parametric form of this equation, i.e.:

x = f(t)
y = f(t)

thanks in advance for the help.

2. Originally Posted by tombrownington
hi all,

given the implicit equation $x^2+x+1-y^2 = 0$, how can i find the parametric form of this equation, i.e.:

x = f(t)
y = f(t)

thanks in advance for the help.
Note:

1. Your cartesian equation can be re-written as $\frac{4}{3} \left( x + \frac{1}{2} \right)^2 - \frac{4}{3} y^2 = -1$.

2. From the Pythagorean Identity: $\tan^2 t - \sec^2 t = -1$.