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Math Help - conversion from cartesian to parametric form

  1. #1
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    conversion from cartesian to parametric form

    hi all,

    given the implicit equation x^2+x+1-y^2 = 0, how can i find the parametric form of this equation, i.e.:

    x = f(t)
    y = f(t)

    thanks in advance for the help.
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  2. #2
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    Quote Originally Posted by tombrownington View Post
    hi all,

    given the implicit equation x^2+x+1-y^2 = 0, how can i find the parametric form of this equation, i.e.:

    x = f(t)
    y = f(t)

    thanks in advance for the help.
    Note:

    1. Your cartesian equation can be re-written as \frac{4}{3} \left( x + \frac{1}{2} \right)^2 - \frac{4}{3} y^2 = -1.

    2. From the Pythagorean Identity: \tan^2 t - \sec^2 t = -1.
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