also for 2logx^2 (base 3) + 2log(3 sqrt x) (base 3) =7 i got x=1.65 is this correct
the first question is 5 ^ (x-2+log 4(base 5))=20 find x? sorry
thanks
???
$\displaystyle 2\log_3x^2+2\log_33\sqrt x=7$
$\displaystyle \Rightarrow\log_3x^4+\log_39x=7$
$\displaystyle \Rightarrow\log_3\left[x^4(9x)\right]=7$
$\displaystyle \Rightarrow\log_39x^5=7$
$\displaystyle \Rightarrow9x^5=3^7$
$\displaystyle \Rightarrow x^5=3^5$
$\displaystyle \Rightarrow x=3.$
$\displaystyle 5^{x-2+\log_54}=20$the first question is 5 ^ (x-2+log 4(base 5))=20 find x? sorry
thanks
$\displaystyle \Rightarrow5^x5^{-2}5^{\log_54}=20$
Can you finish it?