I don't know what this means...? Since the quadratic is negative, the parabola does open downward....

To find the vertex, eithercomplete the squareor elseuse the formula"h = -b/(2a)".

The axis of symmetry is the vertical line "x = h" through the vertex.

To find a givenintercept, plug "0" in for the other variable, and solve. So plug "0" in for "x" and evaluate to find the y-intercept, and then plug "0" in for "y" andsolve the quadratic equationto find the x-intercept(s).

Graphin the usual way: Pick x-values, plug them into the formula, find the corresponding y-values, and draw the dots. Repeat until you are confident of the shape of the curve, and then sketch.

Look at the graph. Look at the vertex. Use what you've learned about the relationship between the vertex of a parabola andthe max/min pointsof quadratics.

The range is the output values. So look at the graph and figure out what values y can achieve. For instance, can y equal 5?

To learn how to answer this, study a lesson onsolving quadratic inequalities.