# Thread: finding the derivative

1. ## finding the derivative

y= (x^3-7)^5 at x=2

2. Originally Posted by joe19
y= (x^3-7)^5 at x=2
Use the chain rule:

If $y =[f(x)]^n$ then $\frac{dy}{dx} = nf'(x)[f(x)]^{n-1}$