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Math Help - finding the derivative

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    finding the derivative

    y= (x^3-7)^5 at x=2
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  2. #2
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    Quote Originally Posted by joe19 View Post
    y= (x^3-7)^5 at x=2
    Use the chain rule:

    If y =[f(x)]^n then \frac{dy}{dx} = nf'(x)[f(x)]^{n-1}
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