Simplify the following function: (sec^2x-1)/(sinx) Thanks for any help!
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Originally Posted by live_laugh_luv27 Simplify the following function: (sec^2x-1)/(sinx) Thanks for any help! use this Pythagorean identity to help ... $\displaystyle 1 + \tan^2{x} = \sec^2{x} $
I did this, and got tan^2x/sinx, and simplified to sinx/cos^2x. Now I'm stuck. Can I simplify this further?
Originally Posted by live_laugh_luv27 I did this, and got tan^2x/sinx, and simplified to sinx/cos^2x. Now I'm stuck. Can I simplify this further? $\displaystyle \frac{\sin{x}}{\cos^2{x}} = \frac{1}{\cos{x}} \cdot \frac{\sin{x}}{\cos{x}} =$ ?
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