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Math Help - [SOLVED] Help with amplitude, period,range and phase shift

  1. #1
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    [SOLVED] Help with amplitude, period,range and phase shift

    okay, i dont remember how to do any of this. so someone please help me.


    Let .
    What is the amplitude? Period? phase shift? and range

    Let .
    What is the amplitude? Period? phase shift? and range

    Let . What is the amplitude? Period? phase shift? and range
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  2. #2
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    Quote Originally Posted by lsnyder View Post
    okay, i dont remember how to do any of this. so someone please help me.


    Let .
    What is the amplitude? Period? phase shift? and range

    Let .
    What is the amplitude? Period? phase shift? and range

    Let . What is the amplitude? Period? phase shift? and range
    The general equation is y = Asin(kx+t) + d

    where:

    A is the amplitude
    1/k is the period
    t is phase shift
    d is range
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  3. #3
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    okay, i can kinda remember most of this material from class. But the only thing i got right (typing in my homework) is the amplitude. So can u show me how u do the phase shift, range and period with at least one of them. I'm sorry but I'm a visual learner to the extreme (which is really sad) and I think I would comprehend better.
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  4. #4
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    y = a sin (bx + c) + d

    |a| is the amplitude: this tells you how tall the curve is at it's highest point from the center.

    (2pi)/|b| is the period: this tells you how long the sin function takes to get its job done. the curve will repeat itself every <period> units

    -c/b is the phase shift: this tells you how far the curve is "scooted over to the right" on the graph. while the period represents shrinking or stretching the coil, the phase shift just moves the whole thing over.

    the range is d-|a| to d+|a|: this tells you the lowest to highest value the curve takes on.


    example:

    y = -8sin (4x - 3) +2

    amp: 8

    per: (2pi)/4 = pi/2

    p.s.: -(-3)/4) = 3/4

    range: -6 to 10

    have fun!
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