A population of 8 million increases at a rate of .1% every month. In how many months will it reach 20 million? Is the formula: 20000000=8000000*(1.01)^(n-1)
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Originally Posted by kcwillia377 A population of 8 million increases at a rate of .1% every month. In how many months will it reach 20 million? Is the formula: 20000000=8000000*(1.01)^(n-1) I think it's ^n instead of ^(n-1) $\displaystyle 20 \times 10^6 = 8 \times 10^6 (1.01)^n$
yeah that's the correct formula...i'm pretty sure...but i could be wrong
How do I solve for n?
Originally Posted by e^(i*pi) I think it's ^n instead of ^(n-1) $\displaystyle 20 \times 10^6 = 8 \times 10^6 (1.01)^n$ Originally Posted by kcwillia377 How do I solve for n? $\displaystyle 1.01^n = \frac{5}{2}$ Take logs: $\displaystyle n\ln(1.01) = ln{\frac{5}{2}}$ $\displaystyle n = \frac{ln(2.5)}{ln(1.01)} = 92.1$
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