Inverse functions

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March 23rd 2009, 05:12 AM
princess_21

Inverse functions

what is the inverse function of 3y=2x+7. How will I do that? thanks
March 23rd 2009, 05:23 AM
chisigma

Any linear function of the type $y= a\cdot x + b$ , $a \ne 0$ has its inverse of the form $x= \frac {1}{a}\cdot (y-b)$ . In your case is $a=\frac {2}{3}$ , $b= \frac{7}{3}$ …

Kind regards

$\chi$ $\sigma$
March 23rd 2009, 05:30 AM
princess_21

Quote:

Originally Posted by chisigma

Any linear function of the type $y= a\cdot x + b$ , $a \ne 0$ has its inverse of the form $x= \frac {1}{a}\cdot (y-b)$ . In your case is $a=\frac {2}{3}$ , $b= \frac{7}{3}$ …

Kind regards

$\chi$ $\sigma$

you mean that the inverse of y=f(x) is x=f(y)?? I will just make it in terms of x

in my question

$3y=2x+7$

$3y-7=2x$

$f(x)=\frac{3y-7}{2}$
March 23rd 2009, 05:38 AM
chisigma

Quote:

Originally Posted by princess_21

you mean that the inverse of y=f(x) is x=f(y)??...

More exactly the inverse of $y=f(x)$ is $x=f^{-1} (y)$

Kind regards

$\chi$ $\sigma$
March 23rd 2009, 05:41 AM
princess_21

[quote=chisigma;286895]More exactly the inverse of $y=f(x)$ is $x=f^{-1} (y)$

can you give an example? i cant understand. $x=f^{-1} (y)$
March 23rd 2009, 06:23 AM
chisigma

Simple examples of couples of 'direct' and 'inverse' functions are...

$y=f(x)=x^{2} \rightarrow x=f^{-1} (y)= \sqrt {y}$

$y= f(x)= \sin x \rightarrow x=f^{-1} (y)= \sin ^{-1} y$

$y= f(x) = e^{x} \rightarrow x=f^{-1} (y)= \ln y$

In it important to take into account that the inverse function often it is not a single value function, just as in three examples I have given…

Kind regards

$\chi$ $\sigma$

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