1. Find the Inverse of:

$\displaystyle f(x)=\frac{2x-1}{x-6}$

My answer was:

$\displaystyle f(x)=\frac{6x-1}{x-2}$

Is this Correct?

2. Find $\displaystyle f{\circ}g$ and $\displaystyle g{\circ}f$ when

$\displaystyle f(x)=x^3-1$ and $\displaystyle g(x)=\sqrt[3]{x=1}$

I got:

$\displaystyle (x+1)^{1/18}-1$

$\displaystyle \text{Thanks for the Help!!!}$