A curve with equation y = ax^2 + bx + c crossed the x-axis at (-4,0) and (0,0) and also passes through the point (2,120). Where does the curve cross the y-axis?
A curve with equation y = ax^2 + bx + c crossed the x-axis at (-4,0) and (0,0) and also passes through the point (2,120). Where does the curve cross the y-axis?
The y-intercept occurs where x = 0.
You're told that the curve passes through the origin.
I knew that and I posted the question wrong .. It should have been (0,9) not (0,0) . It just didn't appear to me that the equation should be made of type a(x - s)(x - r) (or similar) .. I solved it though
A curve with equation y = ax^2 + bx + c crossed the x-axis at (-4,0) and (0,9) and also passes through the point (2,120). Where does the curve cross the y-axis?
You have been given three points, being three sets of values for and . Plug these values into the given equation: