Craig has $6.65 in nickels and dimes on his desk in a jar. If he has 11 less nickels than dimes, how many of each coin does he have?
MY WORK:
Let 5n = nickels
Let 10d = dimes
Then 5n + 10d = 665....This is the first equation.
This is where I got stuck.
Lets see the complete answer
We consider that we have n nickel coins and d dimes coin
We than worked out that the total amount of money (a dime means 10 cents & a nickel coin means 5 cents) we have will be given by
10d (from dime coins) + 5n(from nickel coins) = 665 cents
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
But according to second condition
the number of nickel coins is less than number of dime coins by 11
Hence
d(no. of dime coins) -11= n(no. of nickel coins)
~~~~~~~~~~~~~~~~~~~~~~~~~
Thus the second equation we get is
d -11 = n
You understand, don't you, that "dimes would be 10d" makes no sense at all! Especially since you haven't said what "d" represents.
In other words, write in full, grammatically correct, sentences. What you mean to say is "Let d be the number of dimes and n the number of nickels. Then the value of the coins is 10d for the dimes and 5n for the nickels."
Yes, the fact that he has $6.65 in nickels and dimes means 10d+ 5n= 665.
You are also told, "he has 11 less nickels than dimes", or n= d- 11. Solve those [b]two[b] equations for n and d.