Craig has $6.65 in nickels and dimes on his desk in a jar. If he has 11 less nickels than dimes, how many of each coin does he have?
Let 5n = nickels
Let 10d = dimes
Then 5n + 10d = 665....This is the first equation.
This is where I got stuck.
We consider that we have n nickel coins and d dimes coin
We than worked out that the total amount of money (a dime means 10 cents & a nickel coin means 5 cents) we have will be given by
10d (from dime coins) + 5n(from nickel coins) = 665 cents
But according to second condition
the number of nickel coins is less than number of dime coins by 11
d(no. of dime coins) -11= n(no. of nickel coins)
Thus the second equation we get is
d -11 = n
In other words, write in full, grammatically correct, sentences. What you mean to say is "Let d be the number of dimes and n the number of nickels. Then the value of the coins is 10d for the dimes and 5n for the nickels."
Yes, the fact that he has $6.65 in nickels and dimes means 10d+ 5n= 665.
You are also told, "he has 11 less nickels than dimes", or n= d- 11. Solve those [b]two[b] equations for n and d.